Cubit and an hand breadth. By reckoning the cubit at 17.5 in. (444.5 mm.) and adding a handbreadth (1/6 cu.), Ezekiel’s cubit would be 20.4 in. (518.6 mm.). The measuring reed would then be 10 ft. 2 1/2 in. long (3.12 m.) (see Vol. I, p. 165).
Breadth of the building. That is, the thickness of the wall surrounding the court. The wall is designated A on the temple plan on p. 716. This drawing is offered as an approximate representation of the building and courts (see note under Key).
The height and breadth of the wall are given here as equal. The length is here not given but appears to have been 500 cu. (about 850 ft. [259 m.], see on ch. 42:16) on each of its four sides. This wall was around the outside of the whole complex structure. It was not high (about 10 ft. [3 m.]), and people approaching to worship could easily see the temple in all its beauty and glory shining above the walls.